Question

. Section 1 (General Aptitude) - 25
. Section 2 (About IndiaMART) -5 questions
Duration - 90 Mins
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1. Two pipes can fill a tank in 10 and 14 minutes respectively. A third pipe can empty the tank at the rate of 10 liters/minute. If all the
8 minutes, what is the capacity of the tank?
None of these
157 L
215.4L
200 L​

Answer 1

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Given :-

Two pipes can fill a tank in 10 and 14 minutes respectively. A third pipe can empty the tank at the rate of 10 liters/minute. All the pipes working together can fill the empty tank in 8 minutes.

To find :-

The capacity of the tank.

$\large\bold\red{Solution:- }$

$</p><p></p><p>Let \: the \: capacity \: of \: the \: tank \: is \: X \: liters. \\ </p><p></p><p>10 \: liters \: is \: emptied \: in \: 1 \: minute \\ </p><p>X \: liters \: will \: be \: emptied \: in \: \frac{X}{10} \: minutes. \\ </p><p></p><p>In \: \frac{X}{10} \: minutes \: the \: whole \: tank \: will \: be \: emptied. \\ </p><p></p><p>In \: one \: minute \: \frac{X}{10} \: part \: of \: the \: tank \: will \: be \: emptied.$

$\large\bold\red{As \: per \: question}$

$\frac{1}{10} + \frac{1}{14} - \frac{10}{X} = \frac{1}{8} \\ \frac{10}{X} = \frac{1}{10} + \frac{1}{14} - \frac{1}{8} \\ \frac{10}{X} = \frac{112 + 80 - 140}{1120} \\ \frac{10}{X} = \frac{52}{1120} \\ 52X = 11200 \\ X = \frac{11200}{52} = 215.4 \: litres$

$\huge \fcolorbox{black}{cyan}{♛hope \: it \: helps \: you♛}$