Question

Section 4 of 7 Cognitive AE v
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2.
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Question #4
Revisit
A cupboard has three drawers, one drawer has 6 red and 4 green balls, the other has 5 green
balls and the third one has 4 red balls. One ball is randomly drawn from any one drawer, also
chosen randomly.
What is the probability that the chosen ball is red?.​

Answer 1

Answer:

1/3 (6/10 + 0 + 4/4) = 8/15

so probability that the chosen ball is red is 8/15.

Answer 2

Given: A cupboard has three drawers, one drawer has 6 red and 4 green balls, the other has 5 green balls and the third one has 4 red balls. One ball is randomly drawn from any one drawer, also chosen randomly.

To find: The probability that the chosen ball is red.

Solution:

Since there are three drawers, the probability of taking the ball from any one of the three drawers is 1/3.

Now, the probability of taking a red ball from the first drawer is 6/10. The probability of taking a red ball from the second drawer is 0/5. The probability of taking a red ball from the first drawer is 4/4.

Thus, the probability of choosing a red ball from any of the three given drawers is calculated as follows.

$(\frac{1}{3} * \frac{6}{10}) + (\frac{1}{3} * \frac{0}{5}) + (\frac{1}{3} * \frac{4}{4} ) = \frac{1}{5} + 0 + \frac{1}{3}$

                                           $= \frac{8}{15}$

Therefore, the probability that the chosen ball is red is 8/15.