Question

SECTION - A
1.
Find the value of 'a' if (x + 2) is a factor of p(x) = x3 + 8x2 + 15x + ax - 6.​

Answer 1

Answer:

$(x + 2 )= 0 \\ x = - 2$

$p( - 2) = { - 2}^{3} + 8 { (- 2)}^{2}+ 15( - 2) + a( - 2) - 6 = 0$

$( - 8) + 8(4) - 30 - 2a - 6 = 0$

$- 8 + 32 - 36 - 2a = 0$

$32 - 44 - 2a = 0$

$- 12 - 2a = 0$

$- 2a = - 12$

MINUS & MINUS GETS CANCALLED AND U GET.

$2a = 12 \\ a = \frac{12}{2} \\ a = 6$

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