Question

SECTION A
1.If a and B are the root of the quadratic polynomial px? + qx+r, then find the value of
a” + B3 a
Show that the coware of an odd nositive interach
A.​

Answer 1

Step-by-step explanation:

f(x)=px2 +qx +r;

sum of the roots= alpha+Beta =(-q/p);

product of the roots =alpha*beta= r/p;

Put these values in the expression

1/ (p.alpha+q) + 1/ (p.beta+q)

On solving you will get = q/(pr)

Thanks.

Mark's me as a brainlaist