Question

Section A 1. Preview Result button is present on the _______________________tab. A.Review B.Mailings C.Merge 2. A Formula starts with an _____________________sign. A.Equal to (=) B.plus(+) C.Minus(-) 3. __________________box show the address of an active cell. A.Cell B Name C Formula 4. _________________is the data item ,which instructs Microsoft Word where to insert the data source information in the main document. A.Data Source B.Merge Field C.Main Document 5. _____________is a row on a datasheet ,which consists of a number of fields. A. Field B.Record C.Database Section B 1.Field is a column in a data source that contain one type of information. ( ) 2.Status bar includes the name of the currently selected command or current activity. ( ) 3. Data cannot be entered in an active cell. ( ) 4.A workbook can contain any number of worksheets according to a users’s need. ( ) 5. The Main document consists of a mailing list. ( ) Section C 1. A_________________ mark gives an indication that a record is selected. 2. The _______________________ key helps us to move between fields while typing the data. 3. The _________________ contains the text that we send to all the recipients . 4. A worksheets becomes active by clicking on the _______________ tab. 5. Pressing the ____________________ key opens the Save As dialog box. Section D Q1. Who invented the first Spreadsheet Visi Calc ? Q2Write down any two components of a worksheet.. Q3.Which tab do you select to execute the Mail Merge option? Q4.Which option is used to print a Mail Merge document? Q5.Which part of the data sheet displays one type of information? Section E Q1.What do you understand by the term of Mail Merge ? Q2.What do you understand by Microsoft Excel ?
Answer All the Questions​

Answer 1

Answer:

these big is not allowed because this is not a right questions

Answer 2

Explanation:

Since, each student requires 9m2 of floor and given the no. of students is 50.

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18m

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h                      ⇒5400=450Xh

Since, each student requires 9m2 of floor and given the no. of students is 50.So the total area of the room is 9m2X50=450m2Given the length of the room is 25m, so the Breadth is =450/25=18mSInce, each student requires 108m3 of space , so total volume of the room is 108X50=5400m3we know that : Volume=Area X h                      ⇒5400=450Xh                      ⇒h=5400/450=  12m