Question

Section-A (1M each)
1. How many terms are present in the AP: 11,18,25,... 130
(a) 16
(b) 17
(c) 18
d) 19​

Answer 1

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Answer 2

l=a+(n-1)d
130=11+(n-1)7
130-11=(n-1)7
119/7=(n-1)
17=(n-1)
n=18