Section A consists of 20 questions of 1 mark each. Any 16 questions are to be attempted. 1. What will be the least possible number of the planks, if three pieces of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length?
Answers
Answer:22 planks
Step-by-step explanation: All of the planks have to be divided into the same length so you have to look for a common length that can divide all the planks equally, basically a common factor. In this case it is 7. Therefore 42 will be divided into 6 planks (6 * 7 = 42) and 49 will be 7 planks(7 *7 = 49)and 63 will be 9 planks(7*9 = 63). Therefore the least number of planks = 6 + 7 + 9 = 22planks.
Hope this helps you.
Step-by-step explanation:
the lengths of three pieces of timber are 42 m,49 m and 63 m respectively. we have to divide the timber into equal length of planks.
greatest possible length of each plank =HCF(42,49,63)
The prime factorization of 42,49 and 63 are:
42=2×3×7
49=7×7
63=3×3×7
HCF (42,49,63)=7
the greatest possible length of each plank is 7 m.
so (42 divide by 7)+(49 divide by 7)+(63 divide by 7)
=6+7+9=22
therefore, the number of planks can be formed =22.
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