Physics, asked by chinmayee6540, 1 year ago

SECTION - A.D .
**A man is carrying a block of a certain substance (of density 1000
kgm^-3) weighing 1 kg in his left hand and a bucket filled with water and
weighing 10kg in his right hand. He drops the block into the bucket.
How much load does he carry in his right hand now?​

Answers

Answered by gadakhsanket
25

Hey Dear,

◆ Answer -

Load in right hand = 110 N

● Explaination -

The man drops block of 1 kg in bucket filled with water 10 kg in his right hand.

Total weight in his right hand will be -

Total load = (m1 + m2) g

Total load = (10 + 1) × 10

Total load = 110 N

Hence, the man will carry total 110 N load in his right hand.

Thanks dear...

Answered by AvantikaaLucky41104
3

Explanation:

but the answer given is 10 kg

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