Question

SECTION - A
Objective Type Questions
(Binary Solution, Concentration Terms, Solubility)
1. 100 ml of 1 M NaOH is mixed with 50 ml of 1 N
KOH solution. Normality of mixture is
(1) IN
(2) 0.5 N
(3) 0.25 N
(4) 2N​

Answer 1

Answer:

(1) IN

Explanation:

Volume of Naoh = V1 = 100ml  (Given)

Volume of KOH = V2 = 50ml  (Given)

N1 = 1m and N2 = 1n

To calculate the normality of the solution after mixing 2 solutions, we use the equation:

NV = N1V1 + N2V2/ V1 + V2

Where N1V1 are the normality and volume of the NaOH and N2V2 are the normality and volume of the KOH.

Substituting values in the equation-  

= 150 × N = n × M (100) + 1 × 1 (50) 150 × N

= 1 × 1 (100) + 50 N

= 150/150

= 1

Thus the normality of mixture is 1N.