Question

SECTION -A Q.1-A) Choose the correct alternatives :- (2) 1. AABC and ADEF are equilateral triangles. If A(AABC) : A(ADEF) = 1:2 and AB = 4 then what is the length of DE ? b] 4 c] 8 d] 472 ACR is inscribed in arc Arofa circle with centre of ZACB = 65°, find m(arc ACB) a) 22 2​

Answer 1

Answer:

Draw, AD ⊥ BC

In ΔADB and ΔADC,

AB = AC

AD = AD

∠ADB = ∠ADC {Both are 90°}

Therefore, ΔADB ≅ ΔADC by RHS congruence.

Hence, BD = DC {by CPCT}

In right angled ΔADB,

AB2 = AD2 + BD2

(2a)2 = AD2 + a2

⇒ AD2 = 4a2 – a2

⇒ AD2 = 3a2

⇒ AD = √3a

Answer 2

Answer:

In ∆ABC and ∆DEF,

full answer is in the attachment