Question

SECTION B (15 M)
(5qx3m=15m)
13 An object of height 2 cm is placed perpendicular to the principal axis of a concave lens of
length 5 cm. If the distance of the object from the optical centre of lens is 10 cm,
determine the position, nature and size of the image formed using the lens formula​

Answer 1

h1=2cm

f=-5cm

u=-10cm

Therefore,

1/f=1/v-1/u

-1/5=1/v+1/10

1/v=-1/10-1/5

=>1/v=-3/10

Therefore, v=-10/3cm

So the image is formed at 3.33cm in front of the lens.

Therefore the image formed is virtual and erect .

=>h2/h1=v/u

h2/2=-10/3 x -1/10

Therefore, h2=1/3cm =0.3cm

Therefore Size of image is 0.33cm.

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