Question

SECTION B
Prove that angles opposite to equal sides of an isosceles triangle are equal.la

Answer 1

Step-by-step explanation:

given a ∆ABC,. and AB=AC.

To prove:angle ABC =angle ACB.

CONSTRUCTION:draw AD PERPENDICULAR to BC.

PROOF: In triangle ABD and triangle ACD.

we have. AB=AC( Equal sides)

AD=AD(common)

BD=CD(altitude if isosceles∆ bisects

the base)

Therefore∆ABD is congruent to ∆ACD.

BY CPCT ANGLE ABC =ANGLE ACB