SECTION B
Question numbers 21 10 26 carry 2 marks each.
221. A number is first increased by 20% and then it is decreased by 20%. Find the net increase or decrease (2)
percent.
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Answer:
Step-by-step explanation:
Let the number to be 100
Number Increase by 20%
100 + 20% of 100
= 100 + ((20/100)x100)
= 100 + 20 = 120
Vol 73
260
4.0
The resulting number decreased by its 15%
= 120- (15/100×120)
= 120 - 18
= 102
Now, net increase =102-100 = 2
Increase % = (net increase / Original number x 100) %
= ( 2 / 100 ×100 )%
= 2%.
Hence, the increase percent = 2%
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