Question

SECTION C (2 X2-4)
Q1. Two numbers ar in the ratio 3:5. if the sum of the numbers is 96, find the numbers.​

Answer 1

Answer:

consider the ratios as x

Step-by-step explanation:

: 3x + 5x = 96

:8x=96

:x=96/8

:x=12

: one no is 3×12=36

and another 5×12=60

Answer 2

$\huge{\mathfrak{\overline{\underline{\underline{\blue{Question}}}}}}$

Two numbers ar in the ratio 3:5. if the sum of the numbers is 96, find the numbers.

$\huge{\mathfrak{\overline{\underline{\underline{\blue{Answer}}}}}}$

$\huge\bold{Given}$

The sum of two numbers is = 96

The two Number in the ratio = 3:5

So the number be = 3x And 5x

$\huge\bold{To \:find}$

The number = ?¿

Now :

☞︎︎︎ $3x + 5x = 96$

☞︎︎︎ $8x = 96$

☞︎︎︎ $x =\frac{96}{8}$

☞︎︎︎ $x = \cancel\frac{96}{8}$

☞︎︎︎ $x = 12$

$\huge\bold{x = 12}$

Now let's find the number :

➪ 3x = 3(12) = 36

➪ 5x = 5(12) = 60

$\huge\bf\boxed{\boxed{\underline{\red{So \:the \:number \:are \:36 , \:60}}}}$