Question

SECTION - C:Attempt 5 questions. Each question carries seven marks.
18. Iff: A →B,g:B →C be bijections, then prove that (gof)-1 = f- og​

Answer 1

Step-by-step explanation:

it is an on to function

if f:AtoB is an on to function then

for all y€b there exist x€A then

f(x)=y

if g:BtoC is an onto function then

for allz€c there exist y€B then

g(y)=z