Question

Section - C Attempt any Four (Each 3M) Q.14 Calculate the oxidation number of underlined atoms. a) HNO3 b) SO, c) K2Cr2O7 ​

Answer 1

Answer:

Let the Ox. no. of Cr in K 2Cr 2 O 7 be x.

We know that, Ox. no. of K=+1

Ox. no. of O=−2

So, 2(Ox.no.K)+2(Ox.no.Cr)+7(Ox.no.O)=0

2(+1)+2(x)+7(−2)=0

or +2+2x−14=0

or 2x=+14−2=+12

or x=+ 212 =+6

Hence, oxidation number of Cr in K 2 Cr 2O 7is +6.