Section-C
Each 3 Marks
Q-27. PQR is a triangle right angled at P and M is a point on Q R Such
that PM is perpendicular to QR. Show that PM QMX MR
M
Q-28. Prove that
sin - 2 sin 0/2 cos' - Cos 8 = tan 0.
Q-29. Check whether - 150 is a term of the A.P. 11,8,5.....
Answers
Answer 27:-
In ΔQMP and ΔQPR
<QMP = <QPR (EACH = 90 degree)
<Q = <Q (COMMON)
⇒ ΔQMP SIMILAR ΔQPR ....(1) (AA similarity)
Again in ΔPMR and ΔQPR,
<PMR = <QPR (EACH = 90 degree)
<R = < R (COMMON)
⇒ ΔRMP similar ΔQPR .......(2) (AA similarity)
From (1) and (2) we get
ΔQMP similar ΔPMR
Therefore,
The corresponding sides are proportional
QM/PM = PM/RM
⇒ QM.RM = PM. PM (BY CROSS-MULTIPLICATION)
⇒ PM² = QM.RM
Answer 29:-
a = 11
d = 8 - 11 = - 3
Let - 150 be the nth term of the given A.P.
We know that,
an = a + (n - 1)d
⇒ - 150 = 11 + (n - 1) - 3
⇒ - 150 = 11 - 3n + 3
⇒ (- 150) + (- 14) = - 3n
⇒ - 3n = - 164
⇒ 3n = 164
⇒ n = 164/3
So, it is clear that n is not an integer.
Therefore, - 150 is not a term of the given A.P.
Answer:
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Step-by-step explanation: