Question

SECTION C
Q21.-_in cricket a player's batting average is defined as the total number of runs he/she have scored
divided by the number of times they have been out
batting average
runs scored
no of times out
Total
Not out Batting
average
runs
scored
Name No. of No. of
of
test innings
player matches
Yogita 77 71
Aqsha
Mansi 90
53
Rivi 98
92
Shweta 54
26
(a) Complete the following table
45
2012
1553
1006
3000
1000
21
25
50
25
23​

Answer 1

Answer:

Total score in all 40 innings is

50×40=2000

Total score in other 38 innings

38×48=1824

Therefore sum for Maximum and minimum score is 176

Difference of maximum and minimum score is 172

Maximum+ Minimum = 176

Maximum - Minimum = 172

SOLVING

maximum = 174

Minimum= 2

Answer 2

The question written is not correct, the values mentioned required to be changed a bit. The correct question is solved below.

The maximum Score is 174

The minimum Score is 2

GIVEN:  Total score in 40 innings and Total score in 38 innings
TO FIND: The maximum and minimum score
SOLUTION:
As we are given,

The total score in all 40 innings is

= 50×40

= 2000

Also,

The total score in the other 38 innings is

= 38×48

= 1824

Now, we know,

The Sum of the Maximum and a minimum score

= 2000 - 1824

= 176

And,

The difference between maximum and minimum scores is

= 172

Now, We get

Maximum+ Minimum = 176

Maximum - Minimum = 172

Solving the above-mentioned equations by adding both equations.

               Maximum+ Minimum = 176

          +   Maximum - Minimum = 172  

             2.Maximum + 0             = 348

                Maximum                    = 348/2

                Maximum                    = 174

Therefore, the maximum score is 174.

Now, put the value of the maximum score as 174 in any equation.

Such as

Maximum+ Minimum = 176

174 + Minimum = 176

Minimum = 2

Therefore, the minimum score is 2.

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