Question

SECTION C
Q27.
Find the zeroes of the quadratic polynomial
${x}^{2} - 2 \sqrt{2} x$
and verify the relationship between the zeroes and the
coefficients.​

Answer 1

Answer:

$x=0 \ or \ x=2\sqrt2$

Step-by-step explanation:

$x^2-2\sqrt2x=0\\\therefore \ x(x-2\sqrt2)=0\\\therefore \ x = 0 \ or \ x -2\sqrt2= 0\\\therefore \ x =0 \ or \ x=2\sqrt2\\ Relation \ between \ zeros\\Here \ a=1, \ b = -2\sqrt2, \ c= 0\\sum \ of \ zeros = \frac{-b}{a} = \frac{-(-2\sqrt2)}{1}=2\sqrt2\\multilpication \ of \ zeros = \frac{c}{a}=\frac{0}{1}=0$