Question

Section -C (Three marks each)
9. ITA(0.1) is equidistance from B (5.-3) and C(1,6).then find the value of x and also find
distance AC and BC.​

Answer 1

Answer:

ANSWER

As given Q(0,1) is equidistant from P(5,−3) and R(x,6)

⇒PQ=QR

⇒

(0−5)

2

+(1−(−3))

2

=

(x−0)

2

+(1−6)

2

[ By using disatnce formula =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

]

⇒25+16=x

2

+25

⇒41=x

2

+25

⇒x

2

=16

⇒x=4

Distance between Q(0,1) and R(4,6)

QR=

(4−0)

2

+(6−1)

2

=

4

2

+5

2

=

16+25

=

41

Distance between P(5,−3) and R(4,6)

PR=

(4−5)

2

+(6+3)

2

=

1+81

=

82

How satisfied are you with the answer?