Section -C (Three marks each)
9. ITA(0.1) is equidistance from B (5.-3) and C(1,6).then find the value of x and also find
distance AC and BC.
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ANSWER
As given Q(0,1) is equidistant from P(5,−3) and R(x,6)
⇒PQ=QR
⇒
(0−5)
2
+(1−(−3))
2
=
(x−0)
2
+(1−6)
2
[ By using disatnce formula =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
]
⇒25+16=x
2
+25
⇒41=x
2
+25
⇒x
2
=16
⇒x=4
Distance between Q(0,1) and R(4,6)
QR=
(4−0)
2
+(6−1)
2
=
4
2
+5
2
=
16+25
=
41
Distance between P(5,−3) and R(4,6)
PR=
(4−5)
2
+(6+3)
2
=
1+81
=
82
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