Question

SECTION-D
16. In the figure ABCD is a parallelogram
AEI CD and CF 1 AD, if AB = 16 cm,
AE = 8 cm and CF = 10 cm, Find AD.​

Answer 1

AB=CD since it is a ||gm

area of ABCD=b×h

=CD×AE =16×8

=128cm^2

But area could also be,

area of ABCD=AD×CF=AD×10

=10AD cm^2

now equalising both areas,

128=10AD

AD=128/10

AD=12.8 cm

Answer 2

Question :-

In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.

Answer :-

We have, AE ⊥ DC and AB = 16 cm

∵ AB = CD [Opposite sides of parallelogram]

∴ CD = 16 cm

Now, area of parallelogram ABCD = CD x AE

= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]

Since, CF ⊥ AD

∴ Area of parallelogram ABCD = AD x CF

⇒ AD x CF = 128 cm

⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]

⇒ AD = 128/10 cm = 12.8 cm 10

Thus, the required length of AD is 12.8 cm

Hope it helps ❤ Mrk as brainliest