Question

Section D
35. Factorise the expressions
ii) (2x+4y)²​

Answer 1

Answer:

(2x+4y)²

Let us use the below identity :

(a+b)² = a² + b² + 2ab

In the above expression

a = 2x

b = 4y

Using the above identity

(2x+4y)²

= (2x)² + (4y)² + (2 × 2x × 4y)

= 4x² + 16y² + 16xy

= 4(x² + 4y² + 4xy)

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