Question

Section D
35. In the given figure, AFEC = AGBD and
21 = Z2. Prove that AADE – AABC.
​

Answer 1

Step-by-step explanation:

ANSWER

Given : ΔFECΔFEC≅ΔGDB

EC=BD (by CPCT ) ......(1)

Given ∠1=∠2

AEAD ...................(2)

(Sides opposite to equal angles are equal)

From eq 1 and 2

AE/EC=AD/BAD

DE∣∣BC (Converse of Basic Proportionality Theorem)

∠1=∠3 and ∠2=∠4 [Correspoding angles]

In ΔADE and ΔABC

∠A=∠A.....................(Common)

∠1=∠3.................(proved above)

∠2=∠4 ....................(proved above)

ΔADE∼ΔABC......................[by AAA similarity criterion]