Question

secx - tanx=√3 find general​

Answer 1

find square root of 3

shirt form of sq. root of 3

Answer 2

Answer:

$\frac{1}{cosx} + \frac{sinx}{cosx} = \sqrt{3} \\ \\ \frac{1 + sinx}{cosx} = \sqrt{3} \\ \\ \frac{1 + \cos( \frac{\pi}{2 } - x ) }{ \sin( \frac{\pi}{2} - x) } = \sqrt{3} \\ \\ \frac{2 {cos}^{2}( \frac{\pi}{4} - \frac{x}{2} )}{2 \sin( \frac{\pi}{4} - \frac{x}{2} ) \cos( \frac{\pi}{4} - \frac{x}{2} ) } = \sqrt{3} \\ \\ \cot( \frac{\pi}{4} - \frac{x}{2} ) = \sqrt{3} \\ \\ \tan( \frac{\pi}{4} - \frac{x}{2} ) = \frac{1}{ \sqrt{3} } \\ \\ \frac{\pi}{4} - \frac{x}{2} = n\pi + \frac{\pi}{6} \\ \\ x = \frac{\pi}{6} - 2n\pi$