Math, asked by saranclara14gmail, 10 months ago

(secx-tanx) /secx+tanx=1-2secxtanx+2tan²x​

Answers

Answered by manderekam
3

Answer:

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Answered by UshaDhankhar
6

(secx- tanx)×( secx- tanx)/ (secx+ tanx)× (secx - tanx)

sec^2x + tan^ 2 x- 2secxtanx/ secx^2 x - tan^2x ( which is =1)

sec^2 x can be written as ( 1+ tan^2x)

1+ tan^2x + tan^2 x - 2secxtanx

1- 2secxtanx + tan^2x....Answer

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