Question

(see A - COSA) Cot A+ tan A) = sec A ×tan A​

Answer 1

Step-by-step explanation:

We will do it step by step.

We know that

secA=1/cosA

tanA=sinA/cosA

cotA=cosA/sinA

Taking L.H.S

Step 1.put these formulas in question ,we get

(1/cosA)/[(sinA/cosA)+(cosA/sinA)]

Step 2. After taking L.C.M we get

cosAsinA/cosA(sin^2A+cos^2A)

sinA/sin^2A+cos^2A——(1)

Step 3. We know that

sin^2A+cos^2A=1——(2)

Step 4. Put value from eq. (2)to eq.(1) ,we get

sinA

We can see that

L.H.S = R.H.S

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