see above question and give answer plz. . . . . . in triangle abc
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Hey mate thanks for the question
Hope it helps
AngleB=3AngleC
Putting the value of Angle B
Angle A=2×3Angle C
Angle A=6Angle C
Sum of all angles of triangle =180
AngleA+Angle B +AngleC=180
6AngleC+3AngleC+AngleC=180
10AngleC=180
AngleC=180/10
AngleC=18
So ,
Angle A=6×18=108
Angle B =3×18=54
Please mark as brainiest
Hope it helps
AngleB=3AngleC
Putting the value of Angle B
Angle A=2×3Angle C
Angle A=6Angle C
Sum of all angles of triangle =180
AngleA+Angle B +AngleC=180
6AngleC+3AngleC+AngleC=180
10AngleC=180
AngleC=180/10
AngleC=18
So ,
Angle A=6×18=108
Angle B =3×18=54
Please mark as brainiest
nova5:
check the answer
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