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Here a = 1, b = (a+1) and c = b
As we know that :
Sum of the zeroes = -b/a
=> 2+(-3) = -(a+1)/1
=> 2-3 = -a-1
=> a = -1-2+3
=> a = 0
Product of zeroes = c/a
=> 2×(-3) = b/1
=> -6 = b
=> b = -6
So, the values of a and b will be 0 and -6 respectively. ✔✔
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