Question

See figure 2.19. Find RP and PS using the information given in A PSR.
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Answer 1

Answer:

SR = 6

tan30⁰ = SR/PS

$\frac{1}{ \sqrt{3} } = \frac{6}{ps}$

$ps = 6 \sqrt{3}$

cos30⁰ = PS/PR

$\frac{ \sqrt{3} }{2 } = \frac{6 \sqrt{3} }{pr}$

PR = 12

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