Question

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Answer 1

Answer:

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Step-by-step explanation:

$Question :$

$Find \: the \: zeros \: of \: the \: quadratic \\ polynomial \: x²+7x+10 \: \\ and \: verify \\ the \: relationship \: between \: the \\ zeros \: and \: coefficients.$

$ANSWER:$

$x²+7x+10$

$= x²+5x+2x+10$

$= x(x+5) +2(x+5)$

$= (x+5) (x+2)$

$= x = -5, -2$

$LET, -5 \: be \: α$

$and , -2 \: be \: β$

$VERIFICATION:$

$Sum \: of \: Zeroes = \frac{ - b}{a}$

$= α + β = \frac{ - b}{a}$

$= (-5)+(-2) = \frac{ - 7}{1}$

$= -7 = -7$

$now, product \: of \: zeroes = \frac{c}{a}$

$= αβ = \frac{c}{a}$

$= (-5)×(-2) = \frac{10}{1}$

$= 10 = 10$

$Hence \: \: verified.$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

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