Question

see once options question 17

Answer 1

take @ as theta
given sec@ + tan @ = p .............1
sec²@-tan²@=1 ( we know )
then,(sec@+tan@)(sec@-tan@)=1
then,(sec@-tan@)=1/p ...........2
add 1 and 2 equations
we will get ,
2 sec@ = p+1/p
sec@ = 1/2(p+1/p)
option a is correct