Question

See photo and plz give answer

Answer 1

Answer:

The whole system is accelerating downward from right with acceleration 'a'.

All force and tension are acting as shown in fig. or we can draw tree body diagram.

FBD

Now, applying law of motion

F

net

=mass×acceleration

For FBD is

T

1

−40=4a ...(i)

For FBD (ii)

T=T

1

+T

1

=2T

1

...(ii)

For FBD (iii)

30+T

2

−T

1

=3a ...(iii)

For FBD (iv)

30−T

2

=3a ....(iv)

Now,

Adding eqn. (i), (iii) and (iv)

we get

(T

1

−40)+(30+T

2

−T

1

)+(30−T

2

)=4a+3a+3a

⇒20=10a

⇒a=2ms

−2

From eq. (iv)

30−T

2

=3a

⇒30−T

2

=6

T

2

=30−6=24N

From eqn. (i)

T

1

−40=4a

⇒T

1

=4×2+40=48N

From eqn. (ii)

T

1

−40=4a

⇒T=2T

1

⇒T=2×48

=96N

Hence, a=2m

−2

,T=96N,T

2

=24N,T

1

=42N