Question

See
$2 = \sqrt{2 {}^{2} } \\ \\ 2 = 4 \\ 2 = \sqrt{ - 2 { }^{2} } \\ \\ 2 = - 2 \\ is \: that \: right$
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Answer 1

Answer:

No.....

Step-by-step explanation:

First of all 2 ≠ 4

And +ve 2 and -ve 2 are different

as 2 > 0 and -2 <0

Hope it helps!!!

Answer 2

Answer:

It is false.

Step-by-step explanation:

It has to be known that,  $\sqrt{(x)^{2}} =|x |$

                        And also, $(\sqrt{x} )^{2} =x$

Therefore, $\sqrt{(2)^{2}} =\sqrt{(-2)^{2}} =|2| = 2.$

And 2 ≠ -2.