Question

See the above attachment and plz answer the questions:-

No spams plz!!!!​

Answer 1

Since they are perpendicular, the dot product is zero.

(A is magnitude of vector A, B is magnitude of vector B)

$(\vec A+ \vec B)\cdot (\vec A- \vec B)=0\\</p><p>\implies A^2 -B^2 +\vec A\cdot \vec B - \vec A \cdot \vec B =0\\</p><p>\implies A^2=B^2\\</p><p>\implies \frac{A}{B}=\pm 1$

Answer 2

Answer:

ur answer is

$+ \ - 1$