Question

see the attached file and help me please

Answer 1

In fig number (i)

sin alpha=P/H

=FE/DF

for the value of DF,In triangle DEF

By pythagoras theorem

DF=root 41

now

sin alpha=4/root 41

cos alpha=B/H=DE/DF=5/root41

Tan alpha=P/B=FE/DE=4/5

cot alpha=5/4

cosec alpha=root41/4

sec alpha=root41/5

Step-by-step explanation:

see

very simple to solve

Therefore solve the (ii) part By yourself

In order to know the method of sin,cos,Tan

you can learn that

the line infront of the asked angle would always be perpendicular

and P/B=Tan

P/H=sin

B/H=cos

Thankyou

plaese mark brainliest