Question

See the attached file for the question number 27.

Answer 1

Hey Mate

In the above figure, AD = AC ( given)

So, < d = < c

In triangle ABD

Exterior angle d > angle b ( as exterior angle is greater than its interior opposite angle.)

But < d = < c

=> <c greater than <b

=> AB > AC ( as, side opposite to greater angle is greater in a triangle)

But, AC = AD

So, AB > AD

[ Hence Proved]

Thnku

Answer 2

Here, AD = AC
angle ADC = angle ACD

( exterior angle property says that
angle ABD + angle BAD = angle ADC)
==>. angle ABD < angle ADC
angle ABD < angle ACD
angle ABC < angle ACB

AS, side opposite to greater angle is longer
==>. AC < AB
SO, AD < AB. ( AD = AC

Hence, AB > AD