See the attached QUESTION
And please help me
Answers
Step-by-step explanation:
Solutions :-
6)
Given equation is (k+1)x-(2k+3)y-1 = 0
The point lie on the graph of the equation = (2,3)
=> It is a solution of the given equation
Put x = 2 and y = 3 in the given equation , then
=> (k+1)(2)-(2k+3)(3)-1 = 0
=> (2k+2)-(6k+9)-1 = 0
=> 2k+2-6k-9-1 = 0
=> (2k-6k)+(2-9-1) = 0
=> (-4k)+(2-10) = 0
=> -4k-8 = 0
=> -4k = 8
=> k = 8/-4
=> k = -8/4
=>k = -2
The value of k = -2
Check:-
If k = -2 then the equation becomes
(k+1)x-(2k+3)y-1 = 0
=> [(-2)+1]x-[2(-2)+3]y-1 = 0
=> [-1]x - (-4+3)y-1 = 0
=> -1x-(-1)y-1 = 0
=> -x+y-1 = 0
=> x-y+1 = 0
If x = 2 and y = 3 then LHS
=> 2-3+1
=> 3-3
=> 0
=> RHS
LHS = RHS is true for k = -2
(7)
Let the present age of the father be
X years
1/5th of his age = (1/5)×X years
=> X/5 years
Let the present age of his Son be Y years
According to the given problem
Present age of his Son is 5 years less than (1/5)th the age of father
=> Son's age = (1/5)th of father's age - 5
=> Y = (X/5)-5
=> Y = [X-(5×5)]/5
=> Y = (X-25)/5
=> 5Y = X-25
=> X-25-5Y = 0
=> X-5Y-25 = 0
Answer :-
6)The value of k = -2
7)The required Linear equation in two variables is X-5Y-25 = 0
Step-by-step explanation:
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