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Answer:
(y - 1)(y - 2)(y - 3)
Step-by-step explanation:
y³- 6y² + 11y - 6
Factors of the constant, 6 are ±1, ±2, ±3, ±6.
By substituting y=1, we get
1³- 6×1² + 11×1 - 6 = 1 - 6 + 11 - 6 = 0
So, y - 1 is a factor of the polynomial.
By dividing y³- 6y² + 11y - 6 by y - 1, we get
y² - 5y + 6.
y² - 5y + 6 = y² - 3y - 2y + 6 = y(y - 3) - 2(y - 3)
y² - 5y + 6 = (y - 2)(y - 3)
Therefore,
y³- 6y² + 11y - 6 = (y - 1)(y² - 5y + 6)
=(y - 1)(y - 2)(y - 3)
Hope this helps
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