Question

see the attachment ​

Answer 1

Answer:

(y - 1)(y - 2)(y - 3)

Step-by-step explanation:

y³- 6y² + 11y - 6

Factors of the constant, 6 are ±1, ±2, ±3, ±6.

By substituting y=1, we get

1³- 6×1² + 11×1 - 6 = 1 - 6 + 11 - 6 = 0

So, y - 1 is a factor of the polynomial.

By dividing y³- 6y² + 11y - 6 by y - 1, we get

y² - 5y + 6.

y² - 5y + 6 = y² - 3y - 2y + 6 = y(y - 3) - 2(y - 3)

y² - 5y + 6 = (y - 2)(y - 3)

Therefore,

y³- 6y² + 11y - 6 = (y - 1)(y² - 5y + 6)

=(y - 1)(y - 2)(y - 3)

Hope this helps

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