Math, asked by Anonymous, 5 months ago

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Answered by Anonymous
14

\;\;\underline{\textbf{\textsf{ Given  :-}}}

• Distance between the two inner parallel line segments is = 60 m

(They are each 106m long)

• Wide of the track is = 10 m

\;\;\underline{\textbf{\textsf{ To Find  :-}}}

• The distance around the track along its inner edge.

\;\;\underline{\textbf{\textsf{ Solution  :-}}}

Let the radius of inner semi-circle be r.

Then,

 \leadsto {\sf{ 2r = 60m}} \\ \\

 \leadsto {\sf{ r =  \frac{60}{2} m}} \\ \\

\leadsto {\sf{ r = 30m}} \\ \\

\;\;\underline{\textbf{\textsf{ Hence-}}}

\underline{\textsf{ The radius of inner semi-circle is  \textbf{ 30 m }}}.

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Again :-

 \boxed{\sf{ Distance \: around \: the \: edge \: along \: its \: inner \: edge = AB+ BC + CD + DA}} \\ \\

 \leadsto {\sf{ 106m + \pi \:  \times 30m + 106m + \pi \times 30m}} \\ \\

 \leadsto {\sf{  212m + 2 \times  \frac{22}{7} \times 30m }} \\ \\

 \leadsto {\sf{  212m +   \frac{1320}{7} m}} \\ \\

 \leadsto {\sf{     \frac{1484 + 1320}{7} m}} \\ \\

 \leadsto {\sf{     \frac{2804}{7} m}} \\ \\

\;\;\underline{\textbf{\textsf{ Hence-}}}

\underline{\textsf{The distance around the track along its inner edge is   \textbf{ 400.57m }}}.

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