Physics, asked by Anonymous, 1 year ago

See the attachment!!!!!

^_^

Attachments:

Anonymous: No
Anonymous: how you know it is correct or not?
Anonymous: It's a trivial one.
Anonymous: well,
Anonymous: @Alex57 => waiting for you to answer this =_=
Anonymous: Mavis, you are the most Atittude girl of brainly!!!
Anonymous: stupid girl
Anonymous: same to you :)
Anonymous: Idc spammers, stalkers and rumours ....
Milans88: hm...

Answers

Answered by Milans88
4
Use the Ideal gas equation.
V1/V2=T1/T2
let the area of the base part of cylinder

V2=45+5=50
V1=45-5=40
T1=300K
40/50=300/T2
T2=300×5/4=375K




Anonymous: but I think answer is (d)
Milans88: is the pressure 1.125 i have doubt
Milans88: answer key?
Milans88: I think its E
Anonymous: no,many people here told thstr option d is correct
Anonymous: see the comment section on question
FuturePoet: d may be correct answer
FuturePoet: wait i am solving
Answered by FuturePoet
10
yeah sure for your help


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------------------ Here is your answer ---------------



No 4th is wrong answer 5 th is correct


☆ In this question given a cylinder which is closed at both ends is separated into two equal parts


● Given (45 cm each )

● Temperature of gas 300 k and pressure of 1 atm

● shift the piston 5 cm

● Find Temperature and pressure





use the Ideal equation

v1 /v2 = T1 /T2


v2 = 45 +5 =50

v1 = 45 -5 = 40

T1 =300 k ( given )

40/50 = 300 /T2

T2 = 300 ×5 / 4

T2 = 375 is the correct answer



■ Now hope you understand why (D) is not correct answer and don't be comfuse in pressure it's 1.125 atm



■ it's simple question don't be comfuse about D because sometime answersheet answer which is given may be wrong



☺ As our conclusion your answer is definitely T= 375 k and p = 11.25 atm



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hope you satisfied with my answer



please mark as brainlest as if it helps you





















Milans88: thats what I said
Anonymous: yeah, okay milan :))
Milans88: to brainlestuser
Milans88: he told early d was answer
Anonymous: @Milan , This question was of keam
Milans88: Hm
FuturePoet: by the way this is a question of which class
Anonymous: 11th
FuturePoet: ohhk
Anonymous: great answer,
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