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Answers
Answer:
∠BOC+∠BOA=180
o
[Linear pairs]
⇒44
o
+∠BOA=180
o
⇒∠BOA=136
o
Since diagonals of a rectangle are equal and they bisect each other.
Therefore, in ΔOAB, We have
OA=OB
⇒∠1=∠2[∴ Angle opp. to equal sides are equal]
In ΔOAB, we have
∠1+∠2+∠BOA=180
o
⇒2∠1+136
o
=180
o
⇒2∠1=44
o
⇒∠1=22
o
Since each angles of a rectangle is a right angle.
∠BAD=90
o
⇒∠1+∠3=90
o
⇒22
o
+∠3=90
o
⇒∠3=68
o
Hence, ∠OAD=68
o
Answer:
∠BOC+∠BOA=180
o
[Linear pairs]
⇒44
o
+∠BOA=180
o
⇒∠BOA=136
o
Since diagonals of a rectangle are equal and they bisect each other.
Therefore, in ΔOAB, We have
OA=OB
⇒∠1=∠2[∴ Angle opp. to equal sides are equal]
In ΔOAB, we have
∠1+∠2+∠BOA=180
o
⇒2∠1+136
o
=180
o
⇒2∠1=44
o
⇒∠1=22
o
Since each angles of a rectangle is a right angle.
∠BAD=90
o
⇒∠1+∠3=90
o
⇒22
o
+∠3=90
o
⇒∠3=68
o
Hence, ∠OAD=68
o