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Let assumed mean 'a' = 275
Class
intervalFrequency
fi
mid-point
(xi)
Deviation
di=xi−275
fidi150 - 20014175-100-1400200 - 25026225-50-1300250 - 3001727500300 - 350 23325501150350-400203751002000100450Hence by assumed mean method using formula
xˉ=a+h1i=l∑5=275+1001×450
= 275 + 4.50 = 279.50
Explanation:
yes of course why not
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