see the centre of a circle whose radius is 10 cm find the distance of the chord from the centre if the length of the chord is 12cm
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x = 8
Answer :-
the centre of a circle whose radius is 10 cm find the distance of the chord from the centre if the length of the chord is 12cm
The radius divides the chord into two equal parts.
Let the length of the chord be AB.
Let point P be the point where the radius cuts the chord.
The lengths:
AP = BP
We divide this by 2 to get :
12/2 = 6 cm
The radius to the point where the chord cuts the circle gives the hypotenuse of the right angled formed.
Since the radius is 10 cm we have a right angled triangle whose sides are as follows :
a = h
b = 6
c = 10 cm
By Pythagoras theorem we can get the length a = h
We apply this as follows :
10^2 - 6^2 = 64
h = Square root of 64 = 8
So the distance of the chord from the center is 8 cm.