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Answer:
10,9,8,7,6,5,4,3,2,1
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I don't know the answer
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X + 1/X = √3
Squaring both sides ,
(X+ 1/X)^2 = √3^2
BY THE FORMULA (A+B)^2= A^2 + B^2 + 2AB
X^2 + 1/X^2 + (2 × X × 1/X) = 3
X^2 + 1/X^2 + 2 = 3
X^2 + 1/X^2 = 3 - 2
X^2 + 1/X^2 = 1
Taking LCM of 1 and X^2 ,we get X^2
SO , ( (X^2)×(X^2)+1 ) / (X^2) = 1
(X^4 + 1) / X^2 = 1
X^4/X^2 = 1 -1
X^2 = 0
X = √0
X = 0
and 0 to the power any no. becomes 0 .
so 0+0+0+0+0+0 gives 0 but at last 2 is there so , I have no idea :)
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