Question

See the given pic and solve it ​

Answer 1

Answer:

1 MSD = 0.5 mm

N ( VSD ) = ( N - 1 ) MSD

50 VSD = 49 MSD

1 VSD = 49 / 50 MSD = 49 / 50 × 0.5

:. Least count = 1 MSD - 1 VSD = 0.5 - 49 / 50 × 0.5

→ ( 1 - 49 / 50 ) 0.5

Least count = 1 / 50 × 0.5 = 0.01 mm

The minimum inaccuracy in the measurement of distance = 0.01 mm

Answer 2

$0.01 \: is \: the \: answer$

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