Question

see the image and tell the answer​

Answer 1

Answer:

7-3√2 / 31

Step-by-step explanation:

1 / 7+3√2

1 / 7+3√2 x 7- 3√2 / 7 - 3√2

7-3√2 / (7+3√2) (7-3√2)

7-3√2 / (7)² - (3√2)² (as (a+b)(a-b) = a²-b²)

7-3√2 / 49 - (3 x 3 x √2 x √2)

7-3√2 / 49 - (9 x 2)

7-3√2 / 49-18

7-3√2 / 31

hope this helps :)

please mark me brainliest, thanks

Answer 2

Step-by-step explanation:

GIVEN:

• $\bf{\dfrac{1}{7+3 \sqrt{2}}}$

TO DO:

• We need to rationalise the denominator.

SOLUTION:

➔ $\bf{\dfrac{1}{7+3 \sqrt{2}}}$

Rationalisation is nothing but, removing the √ sign in denominator by using several identities.

On multiplying 7-3√2 on both the numerator and denominator side:

➔ $\bf{\dfrac{1 \times 7-3 \sqrt{2}}{7+3 \sqrt{2} \times 7-3 \sqrt{2}}}$

• We can notice that the denominator is in the form of (a+b) × (a-b). Now, we are going to use the following identity on the denominator side: (a+b)(a-b) = a²-b²

➔ $\bf{\dfrac{7-3 \sqrt{2}}{7 {}^{2} - (3 \sqrt{2}) {}^{2}}}$

➔ $\bf{\dfrac{7-3 \sqrt{2}}{49-18}}$

➔ $\pink{\bf{\dfrac{7-3 \sqrt{2}}{31}}}$

As the radicals or the √ symbols are removed in the denominator, we got the final answer.

Hence, solved!