Question

see the image given in the question

Answer 1

Answer:

given quadratic equation is

a ² + 2x + a = 0.

since, roots are equal

so, discriminant = 0

=> B² - 4AC = 0

=> 2² -4*a*a = 0

=> 4 - 4a² = 0

=> 4a² = 4

=> a² = 1

=> a = √1

thus, a = ± 1.

$.$

Answer 2

Answer:

GIVEN:

$a {x}^{2} + 2x + a = 0$

●ROOTS ARE EQUAL.

TO FIND:

VALUE OF a.

SOLUTION:

AS ROOTS ARE EQUAL THEN DISCRIMINANT IS EQUAL TO 0.

=>b^2-4ac=0

=>b^2- 4a^2=0

=>2^2-4a^2=0

=>4-4a^2=0

=>4a^2=4

=>a^2=4/4=1

=>a=1.