Question

SEE THE PIC AND ANSWER 10 TH QUESTION.....
QUADRATIC EQUATIONS CLASS 10​

Answer 1

Answer:

3

Step-by-step explanation:

This is a type of nested radical problem, which seems impossible to solve, but is pretty easy to solve.

So, let as assume that $\sqrt{6 +\sqrt{6 + \sqrt{6+...}}$ = X

Here comes the plot twist..

Notice that the terms inside the root is a never ending sequence of the same thing. So, for now, concentrate on the terms after the first $\sqrt{6 +}$ term. You can notice that it is still the same , i.e. , $\sqrt{6 +\sqrt{6 + \sqrt{6+...}}$

This is because it continues till infinity.

So, the term after the first $\sqrt{6 +}$ term is also same as X.

Then,

$\sqrt{6+X} = X$

Squaring both sides,

$6 + X = X^{2}$

Rearranging,

$X^{2} - X - 6 = 0$

Finding the roots,

X = 3 [OR] X = -2

X = -2 is not possible since square root of a number cannot be negative. [Remember that X = , $\sqrt{6 +\sqrt{6 + \sqrt{6+...}}$ ]

Thus, the value of  $\sqrt{6 +\sqrt{6 + \sqrt{6+...}}$ = 3

PLEASE MARK BRAINLIEST

Answer 2

Your answer is above.....

Pls refer to it.....

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