Math, asked by srujan3, 1 year ago

see the picture and answer the question urgently

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Answered by danoct2004

Let speed of faster car = x Km/ h Speed of slower car = y km /h Relative speed when both car travels in same direction = x - y If the cars travel in the same direction at different speeds, they meet in 5 hours Speed = distance/ time Total distance = 100 km Speed x – y = 100/5 X – y = 20 Add y both side we get X = 20 + y …(1) Relative speed when both car travels in opposite direction = x + y If they travel towards each other, they meet in 1 hour. Speed = distance/ time Total distance = 100 km Speed x + y = 100/1 Plug the value of x form equation first we get 20 + y + y = 100 2y = 80 Y = 40 Plug the value of y in equation first we get X = 20 + 40 X = 60

srujan3: please give me stage by stabe plz

danoct2004: LET THE SPEEDS OF THE CAR BE X AND Y KMPH
CASE 1.
WHEN GOING IN SAME DIRECTION
RELATIVE SPEED =X-Y
DISTANCE =100 KM
TIME =100/(X-Y)=5 HRS
X-Y=100/5=20.............................I

CASE 2.
WHEN GOING IN OPPOSITE DIRECTION
RELATIVE SPEED =X+Y
TIME =100/(X+Y)=1 HRS
X+Y=100......................II
EQN.I+EQN.II
2X=120
X=120/2=60
Y=100-X=100-60=40
HENCE SPEEDS OF 2 CARS ARE 60 AND 40 KMPH

danoct2004: LET THE SPEEDS OF THE CAR BE X AND Y KMPH
CASE 1.
WHEN GOING IN SAME DIRECTION
RELATIVE SPEED =X-Y
DISTANCE =100 KM
TIME =100/(X-Y)=5 HRS
X-Y=100/5=20

CASE 2.
WHEN GOING IN OPPOSITE DIRECTION
RELATIVE SPEED =X+Y
TIME =100/(X+Y)=1 HRS
X+Y=100......................II
EQN.I+EQN.II
2X=120
X=120/2=60
Y=100-X=100-60=40
HENCE SPEEDS OF 2 CARS ARE 60 AND 40 KMPH

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