see the picture for info. how much current will flow through wire CD. keep all wire resistances negligible.
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000aditya000:
r u in 12 then follow kirchoff's law
i am in 10
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the answer is no current will flow through cd according to wheat stone bridge principle
according to wjeat stone bridge primciple resistence a,b,c,d will be in ratio of a/c = b/d
where a,b are in left and c,d are in right
according to wjeat stone bridge primciple resistence a,b,c,d will be in ratio of a/c = b/d
where a,b are in left and c,d are in right
but what does the law state?
the law states that the current outpit gets cancelled from opposite dorection when a circuot like this has been made
direction*
what
Bro ur answer is wrong!!It is not balanced Wheatstone bridge
it is balanced
btw according to the ques. we should find current through CD
in other words
it follows kirchoff's law junction cancellation
Dude,6/3 is not equal to 3/6
Answered by
0
if you keep all wire resistance negligible then obviously the current will flow and the value of current is 14Ampere.
hnn cd mein current nikal sakte hein as we know the value of 4 resistor
bhai ja ratio satiafy ho jata h to no current passes through the #MIDDLE wire
sl arora ka photo h chahiye to usse refer kr le
acha tum bolna chaheto ho if P/Q=R/S then it's satisfy
k no problm it is also truee
yes
yahh r8
no current passes through cd
as it follows the above rule
How no current passes through this!!?
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